Sin^2x+2cos=2

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Solution for Sin^2x+2cos=2 equation: 


Simplifying
Sin2x + 2cos = 2

Reorder the terms:
2cos + in2xS = 2

Solving
2cos + in2xS = 2

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1in2xS' to each side of the equation.
2cos + in2xS + -1in2xS = 2 + -1in2xS

Combine like terms: in2xS + -1in2xS = 0
2cos + 0 = 2 + -1in2xS
2cos = 2 + -1in2xS

Divide each side by '2os'.
c = o-1s-1 + -0.5in2o-1s-1xS

Simplifying
c = o-1s-1 + -0.5in2o-1s-1xS

Reorder the terms:
c = -0.5in2o-1s-1xS + o-1s-1

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